By Alexander K Hartmann
"This special ebook is a musthave for any scholar trying first steps in machine simulations. Any new scholar becoming a member of my computational physics crew is anticipated to first paintings via Hartmann's consultant prior to beginning a examine project." Helmut Katzgraber affiliate Professor Texas A&M collage "This e-book is choked with beneficial details for everybody doing desktop simulations. it's going to have kept me quite a bit time in my past paintings if it have been to be had then. it may be obligatory analyzing for college students commencing within the box, yet skilled employees also will locate worthy gem stones, as I did." A Peter younger study Professor of Physics collage of California, Santa Cruz This booklet teaches you all useful (problemindependent) instruments and methods had to enforce and practice subtle clinical numerical simulations. therefore, it really is suited to undergraduate and graduate scholars who are looking to turn into specialists in desktop simulations in Physics, Chemistry, Biology, Engineering, machine technology and different fields.
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Additional resources for Big Practical Guide to Computer Simulations
G. =0) or (counter % 2==1) or right away (counter % 2). page 19 09-Oct- 2014 October 9, 2014 20 14:51 Big Practical Guide to Computer Simulations book4˙2nd Big Practical Guide to Computer Simulations ﬁrst occurrence of true for a sequence of || operators. This can be dangerous when using, inside a compound conditional expression, operators which change variables, like the post-increment operator ++, as used in (num_particles > 100)&&(num_run++ > 100). In this case, it depends on the result of the ﬁrst condition whether the post-increment operator in the second condition is performed or not.
This is even the case if 5/3 is assigned to a variable of type double! g. 5%3 results in 2. Note that the modulus operator is not allowed for one or two double or float operands. Nevertheless, in general, if a binary operator combines objects of diﬀerent types, the value having lower resolution will be converted internally to the higher resolution. Consequently, the type of an expression will be always of the highest resolution. On the other hand, when assigning the result of an expression to a variable of lower resolution (or when passing parameters to functions as in Sec.
In void *addressA; int *addressB; addressB = (int *) addressA+1; addressB will point 4 bytes behind addressA, while without the cast it would point only one byte behind addressA. As pointed out in the last section, *address refers to the content of the variable where address points to. Hence, one can change the content of this variable also by using *address on the left side of an assignment, like in int sum; int *address1; sum = 12; address1 = ∑ *address1 = -1; printf("%d \n", sum); which will result in printing the value -1 when the program is executed.